left rotation of elements in the array

#include<stdio.h>
int main() {
  int a[100],n,pos,val,i,k,m;
  scanf("%d",&n);
  for(i=0;i<n;i++)
  scanf("%d",&a[i]);
  scanf("%d",&m); // m specifies number of times to be rotated
  for(k=0;k<m;k++)
  {
  val=a[0];
 for(i=0;i<n;i++)
  {
      a[i]=a[i+1];
  }
 a[n-1]=val;
  }
 printf("elements after left rotation are\n");
  for(i=0;i<n;i++)
  printf(" %d",a[i]);
}

i/p: 5

1 2 3 4 5

3

o/p: elements after left rotation are

 4 5 1 2 3