1. Write a program in C to display the n terms of even natural number and their sum.
SOURCE CODE:
#include<stdio.h>
int main(){
int n,i=1,c=1,sum=0;
printf("Enter number of terms : ");
scanf("%d",&n);
printf("Even natural numbers are : \n");
while(c<=n){
if(i%2==0){
printf("%d ",i);
sum=sum+i;
c++;
}
i++;
}
printf("\nSum of even natural numbers is: %d\n",sum);
return 0;
}
OUTPUT:
Enter number of terms : 5
Even natural numbers are :
2 4 6 8 10
Sum of even natural numbers is: 30
2. Write a program in C to display the n terms of harmonic series and their sum. 1 + 1/2 + 1/3 + 1/4 + 1/5 ... 1/n terms.
SOURCE CODE:
#include<stdio.h>
int main(){
int n,i;
float sum=0;
printf("Enter range:");
scanf("%d",&n);
printf("Series is:\n");
for(i=1;i<=n;i++){
printf("1/%d",i);
if(i<n)
printf("+");
sum = sum + (float)1/i;
}
printf("\nSum of series is: %f",sum);
return 0;
}
OUTPUT:
Enter range:5
Series is:
1/1+1/2+1/3+1/4+1/5
Sum of series is: 2.283334
3. Write a C program to check whether a given number is an Armstrong number or not.
SOURCE CODE:
/*Program to check whether the given number is Armstrong number or not.*/
#include<stdio.h>
#include<math.h>
int main(){
int n,temp,arm=0,c=0;
printf("Enter number:");
scanf("%d",&n);
temp=n;
while(temp>0){
temp=temp/10;
c++;
}
temp=n;
while(temp>0){
arm=arm+pow((temp%10),c);
temp=temp/10;
}
if(n==arm)
printf("Given number is Armstrong.");
else
printf("Given number is not Armstrong.");
return 0;
}
OUTPUT-1:
Enter number:371
Given number is Armstrong.
OUTPUT-2:
Enter number:151
Given number is not Armstrong.
SOURCE CODE:
#include<stdio.h>
int main(){
int n,i=1,c=1,sum=0;
printf("Enter number of terms : ");
scanf("%d",&n);
printf("Even natural numbers are : \n");
while(c<=n){
if(i%2==0){
printf("%d ",i);
sum=sum+i;
c++;
}
i++;
}
printf("\nSum of even natural numbers is: %d\n",sum);
return 0;
}
OUTPUT:
Enter number of terms : 5
Even natural numbers are :
2 4 6 8 10
Sum of even natural numbers is: 30
2. Write a program in C to display the n terms of harmonic series and their sum. 1 + 1/2 + 1/3 + 1/4 + 1/5 ... 1/n terms.
SOURCE CODE:
#include<stdio.h>
int main(){
int n,i;
float sum=0;
printf("Enter range:");
scanf("%d",&n);
printf("Series is:\n");
for(i=1;i<=n;i++){
printf("1/%d",i);
if(i<n)
printf("+");
sum = sum + (float)1/i;
}
printf("\nSum of series is: %f",sum);
return 0;
}
OUTPUT:
Enter range:5
Series is:
1/1+1/2+1/3+1/4+1/5
Sum of series is: 2.283334
3. Write a C program to check whether a given number is an Armstrong number or not.
SOURCE CODE:
/*Program to check whether the given number is Armstrong number or not.*/
#include<stdio.h>
#include<math.h>
int main(){
int n,temp,arm=0,c=0;
printf("Enter number:");
scanf("%d",&n);
temp=n;
while(temp>0){
temp=temp/10;
c++;
}
temp=n;
while(temp>0){
arm=arm+pow((temp%10),c);
temp=temp/10;
}
if(n==arm)
printf("Given number is Armstrong.");
else
printf("Given number is not Armstrong.");
return 0;
}
OUTPUT-1:
Enter number:371
Given number is Armstrong.
OUTPUT-2:
Enter number:151
Given number is not Armstrong.
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